Task: "Individually estimate the diameter of the smallest steel wire that could suspend a typical American automobile." "You have 60 seconds to make an individual estimate. Record your answer and the strategy you used to arrive at your answer. Volunteer your answer so we can determine the range of individual estimates."
After 60 seconds, call for volunteers to give their estimate of the diameter. Record their answers. Often the range is quite large, from "the thickness of a hair" to one inch. Ask how a better answer could be found. Probe what quantities should determine how much load a wire can hold. Record the list of quantities. It will usually include the material and the cross-sectional area of the wire and the way the wire was made.
"Join with your triad and make a joint estimate. You have ten minutes to do so. Develop a model to use for refining your estimate. Record your answer and your model."
If (or when) students say they're done, ask them if they would be willing to hang a car by their wire from a helicopter hovering at 5,000 feet.
After 10-15 minutes ask students to stop working, find a partner in an adjacent group, and explain their group's answer and model.
After 5-10 minutes, ask the students to pause and randomly call on individuals to present their group's answer and method. Record the diameter and their method on the overhead.
Explore the relationship between the load and the cross-sectional area. The bigger the wire is, the more load it should be able to hold. The load in the wire divided by the cross-sectional area is called the stress in the wire. This stress is surprisingly constant across the area. By experimenting with various materials, we can find the stress that each can take without breaking, and the resulting values are referred to as breaking strengths, or failure stresses, of the materials. These quantities are not absolute, as different batches of the same material have some slight variation. But they are close enough to be usable by engineers.
The breaking strengths of various steels range from 60,000 pounds per square inch (psi) of area to 200,000 pounds per square inch. Let's assume that the steel wire we're using has a breaking strength of 100,000 psi (ascertained by calling the manufacturer, or testing a piece ourselves). Let's examine a little section at the top of the wire, and derive a relationship between the quantities of interest. At equilibrium, the forces pulling up on the wire must be the same as the forces pulling down. Furthermore, let's assume that the weight of the wire is very much less than the automobile's weight, so we will ignore it. The equilibrium relationship tells us that
sA = W
s = W/A
s = W/
r2
where s = stress = load/area; A = area (
r2 for a circle); W = automobile weight
For a breaking stress of 100,000 psi, and a load of 2000 lbs, this relationship will tell us that for our example, the diameter is 0.16 inch, or slightly over 5/32 inch, since

Would you actually go out and hang by this wire? No way for me! First or all, any flaw in the wire or error in my assumptions would drop me from the helicopter. Second, I would worry about how steady a platform the helicopter was and how the attachments might weaken the wire. I would definitely want a safety factor. How big a safety factor would be a matter of judgment, since it would depend upon how much I value life, money, and so on. However, if I could design the attachment, if I trusted the weather and the helicopter pilot, and if the manufacturer assured me that the strength of the wire was at least 100,000 psi, I might be talked into hanging on a wire with a diameter of 5/16 inch, since the cross-sectional area would be about four times as large.
What steps would you take to refine your answer? For example, were we justified in ignoring the weight of the wire? Let us call the length of the wire l inches. Our relationship now becomes
s= [W + (
x r2 x l x D)]/A
(where D is the density of the wire. For steel, D = 0.283 lbs/in3). Let us assume that our wire is 1/4 mile ling. The diameter would have to be 0.17 inches. Not much change in diameter from before. We were probably all right in neglecting the weight of the wire
Explore the effect of other assumptions and parameters. For example, what would the diameter of an aluminum wire have to be, or what is the effect of acceleration (Could you jump out of the helicopter?)
Ask the students to summarize their major learnings, and to think of similar situations where their learnings apply.